48z^2+48z+9=0

Solution for 48z^2+48z+9=0 equation:

48z^2+48z+9=0

a = 48; b = 48; c = +9;
Δ = b2-4ac
Δ = 482-4·48·9
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24}{2*48}=\frac{-72}{96}
=-3/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24}{2*48}=\frac{-24}{96}
=-1/4
$